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Physics Velocity...How far must the cars travel for the faster car to arrive 19 min before the slower car?
Two cars travel westward along a straight
highway, one at a constant velocity of
83 km/h, and the other at a constant velocity
of 116 km/h.
How far must the cars travel for the faster car
to arrive 19 min before the slower car?
Answer in units of km.
How in the world do I do this??
Two cars travel westward along a straight highway, one at a constant velocity of 83 km/h, and the other at a constant velocity
of 116 km/h.
How far must the cars travel for the faster car to arrive 19 min before the slower car?
Answer in units of km.
Let t = time for fast car
t + 19 = time for slow car
Distance for fast car = 116 * t
Distance for slow car = 83 * (t + 19)
Distance for fast car = Distance for slow car
116 * t = 83 * (t + 19)
116 * t = 83 * t + 1577
33 * t = 1577
t = 47.79 hr
Distance = 116 * 47.79 = 5543.64 km
Distance = 83 * (47.79 + 19) = 5543.57 km
The difference is due to rounding!!
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